Для удобства читателя номер формулы совпадает с номером соответствующей формулы основного текста книги в гауссовой системе СГС.

\[
\begin{array}{c}
\mathbf{p}=4 \pi \varepsilon_{0} a^{3} \mathbf{E} . \\
C=4 \pi \varepsilon_{0} \varepsilon a .
\end{array}
\]
\[
\begin{array}{r}
C=4 \pi \varepsilon_{0} \varepsilon \frac{R_{1} R_{2}}{R_{2}-R_{1}} . \\
C=\frac{\varepsilon_{0} \varepsilon S}{d} .
\end{array}
\]
\[
C=\frac{2 \pi \varepsilon_{0} \varepsilon l}{\ln (b / a)} .
\]
\[
C=\frac{2 \pi \varepsilon_{0} \varepsilon l}{\ln \left(4 h^{2} / a b\right)} .
\]
\[
W=\frac{q^{2}}{2 C}=\frac{1}{2} q \varphi=\frac{1}{2} C \varphi^{2} \text {. }
\]
\[
w=\frac{1}{2} \mathbf{E D}=\frac{\varepsilon_{0} \varepsilon E^{2}}{2}=\frac{D^{2}}{2 \varepsilon_{0} \varepsilon} .
\]
\[
w=\int \mathbf{E} d \mathbf{D} .
\]
\[
U=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r_{12}} .
\]
\[
d U=T d S+\mathbf{E} d \mathbf{D} .
\]
\[
d \Psi=-S d T+\mathbf{E} d \mathbf{D} .
\]
\[
d \Phi=-S d T-\mathbf{D} d \mathbf{E} .
\]
\[
d I=T d S-\mathbf{D} d \mathbf{E} .
\]
\[
\Psi=\frac{\varepsilon_{0} \varepsilon E^{2}}{2}+\Psi_{0}=\frac{D^{2}}{2 \varepsilon_{0} \varepsilon}+\Psi_{0} .
\]
\[
\begin{array}{c}
U=\left(1+\frac{T}{\varepsilon} \frac{\partial \varepsilon}{\partial T}\right) \frac{\varepsilon_{0} \varepsilon E^{2}}{2}+ \\
+U_{0}(T, \tau) .
\end{array}
\]
\[
f=-w=-\frac{D^{2}}{2 \varepsilon_{0} \varepsilon}=-\frac{\varepsilon_{0} \varepsilon E^{2}}{2} .
\]
\[
\begin{array}{c}
f=\left(\mathscr{P}-\mathscr{P}_{0}\right)-\left(\varepsilon+\tau \frac{\partial \varepsilon}{\partial \tau}\right) \frac{\varepsilon_{0} E^{2}}{2} . \\
f=\frac{\varepsilon_{0}}{2}\left(\varepsilon_{1}-\varepsilon_{2}\right) E^{2} . \quad(32.9) \\
f=\frac{D^{2}}{2 \varepsilon_{0} \varepsilon}\left(\frac{1}{\varepsilon_{2}}-\frac{1}{\varepsilon_{1}}\right) \cdot(33.5) \\
\mathscr{T}=-\mathscr{P}+\frac{\varepsilon_{0} E^{2}}{2}\left(\varepsilon+\tau \frac{\partial \varepsilon}{\partial \tau}\right) . \\
\Pi=\mathscr{P}+\frac{\varepsilon_{0} E^{2}}{2}\left(\varepsilon-\tau \frac{\partial \varepsilon}{\partial \tau}\right) .
\end{array}
\]
\[
\begin{array}{c}
\mathbf{f}=-\operatorname{grad} \mathscr{P}+\rho \mathbf{E}-\frac{\varepsilon_{0} E^{2}}{2} \operatorname{grad} \varepsilon+ \\
+\frac{\varepsilon_{0}}{2} \operatorname{grad}\left(\tau \frac{\partial \varepsilon}{\partial \tau} E^{2}\right) \cdot \quad(34.5) \\
\mathbf{p}=\varepsilon_{0} \beta \mathbf{E} .
\end{array}
\]
\[
\beta=4 \pi a^{3} \text {. }
\]
\[
\frac{\varepsilon-1}{\varepsilon+2}=\frac{1}{3} n \beta \text {. }
\]
\[
\mathbf{P}=\frac{n p_{0}^{2}}{3 k T} \mathbf{E} \text {. }
\]
\[
\alpha=\frac{n p_{0}^{2}}{3 k T \varepsilon_{0}} .
\]
\[
\varepsilon=1+\frac{n p_{0}^{2}}{3 k T \varepsilon_{0}} \text {. }
\]
\[
\mathbf{j}=n e \mathbf{u} \text {. }
\]
\[
\mathbf{j}=\lambda \mathbf{E} \text {. }
\]
\[
\lambda=\frac{n e^{2}}{m} \bar{\tau} .
\]
\[
Q=(\mathbf{j E})=\lambda \mathbf{E}^{2}=\frac{1}{\lambda} \mathbf{j}^{2}
\]
\[
\varphi_{1}-\varphi_{2}+\mathscr{E}=I R .
\]
\[
R=\frac{\varepsilon \varepsilon_{0}}{C \lambda} .
\]

\[
\begin{array}{c}
w=\frac{1}{2}(\mathbf{E D}+\mathbf{H B}) . \\
m \dot{\mathbf{v}}=e(\mathbf{E}+[\mathbf{v B}]) . \\
\mathbf{v}_{\text {д }}=\frac{[\mathbf{E B}]}{B^{2}} . \\
\mathbf{v}_{\text {д }}=\frac{1}{B^{2} e}[\mathbf{F B}] . \\
\mathbf{v}_{\text {д }}=\frac{m v_{\perp}^{2}}{2 e B^{2}} \frac{\partial B}{\partial N} \mathbf{b} . \\
\mathbf{v}_{\text {д }}=\frac{m v_{\perp}^{2}}{2 e B R} \mathbf{b} . \\
\mathbf{v}_{\text {д }}=\frac{m v_{\|}^{2}}{e B R} \mathbf{b} .
\end{array}
\]
\[
\begin{array}{c}
\mathbf{H}=\frac{1}{4 \pi r^{3}}[\dot{\mathbf{p}} \mathbf{r}]_{t-r / v}+ \\
+\frac{1}{4 \pi v r^{2}}[\ddot{\mathbf{p} r}]_{t-r / v} \quad(141.10) \\
\mathbf{D}=\frac{1}{4 \pi}\left[\frac{(\ddot{\mathbf{p}} \mathbf{r})}{v^{2} r^{3}} \mathbf{r}-\frac{\ddot{\mathbf{p}}}{v^{2} r}\right]_{t-r / v}= \\
=\frac{1}{4 \pi v^{2} r^{3}}\left[[\ddot{\mathbf{p}} \mathbf{r}]_{t-r / v}\right. \\
\mathbf{H}=\frac{1}{4 \pi v r^{2}}[\ddot{\mathbf{p} r}]_{t-r / v} \quad(141.11) \\
\mathbf{S}=\frac{\sin ^{2} \vartheta}{16 \pi^{2} \varepsilon_{0} \varepsilon v^{3} r^{2}} \ddot{\mathbf{p}}_{t-r / v}^{2} \mathbf{N} . \quad(141.13) \\
-\frac{d \mathscr{E}}{d t}=\frac{1}{6 \pi \varepsilon_{0} \varepsilon v^{3}} \ddot{\mathbf{p}}_{t-r / v}^{2} \quad(141.14) \\
-\frac{\omega^{4}}{d t}=\frac{e^{2}}{12 \pi \varepsilon_{0} \varepsilon v^{3}} \mathbf{p}_{0}^{2} . \quad(141.16) \\
-\frac{d \mathscr{E}}{d t}=\frac{e^{2}}{6 \pi \varepsilon_{0} \varepsilon v^{3}} \\
D=\frac{1}{\mu_{0} \mu \lambda} . \\
l \sim \frac{1}{\sqrt{2 \mu_{0} \mu \lambda
u}} .
\end{array}
\]